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Bob pulls a block parallel to the surface of plane. The block has a mass of 4.00 kg and can slide along a rough plane inclined 30.0° to the horizontal. The coefficient of static friction between block and the plane is 0.300. What tension is required for the block to start moving?

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Final answer:

The tension required for the block to start moving is approximately 10.14 N.

Step-by-step explanation:

To find the tension required for the block to start moving, we can first calculate the gravitational force acting on the block. The gravitational force can be calculated using the formula:

Fg = mg

where Fg is the gravitational force, m is the mass of the block, and g is the acceleration due to gravity. In this case, the mass of the block is 4.00 kg, and the acceleration due to gravity is approximately 9.8 m/s^2.

Fg = (4.00 kg)(9.8 m/s^2) = 39.2 N

The force required to overcome static friction and start the block moving is equal to the maximum static friction force. The formula for static friction is:

Fstatic = μs * Fn

where Fstatic is the maximum static friction force, μs is the coefficient of static friction, and Fn is the normal force. The normal force can be calculated using:

Fn = m * g * cosθ

where θ is the angle of the incline. In this case, θ = 30.0°.

Fn = (4.00 kg)(9.8 m/s^2)(cos30.0°) = 33.8 N

Finally, we can calculate the maximum static friction force:

Fstatic = (0.300)(33.8 N) = 10.14 N

Therefore, the tension required for the block to start moving is approximately 10.14 N.


User Kannan Ramamoorthy
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