Question

A bobsledder starting from rest accelerates down a hill at a rate of 9.5 m/s^2. If the bottom of the hill is 57 m from the top, what speed (in m/s) will the bobsledder reach by the time it reaches the bottom of the hill? Round your answer to 1 decimal place and do not include units.

A. 26.5 m/s
B. 27.4 m/s
C. 28.3 m/s
D. 29.2 m/s

Answer 1

The bobsledder, starting from rest, accelerates down the hill at 9.5 m/s². Utilizing the kinematic equation vf² = vi² + 2ad, where vi is 0, a is 9.5 m/s², and d is 57 m, the final velocity vf is approximately 27.4 m/s. Hence, option B is the correct answer.

Step-by-step explanation:

The bobsledder starts from rest and accelerates down the hill at a rate of 9.5 m/s^2. To find the speed at the bottom of the hill, we can use the equation: vf^2 = vi^2 + 2ad. where vf is the final velocity, vi is the initial velocity (which is 0 in this case), a is the acceleration, and d is the distance. Plugging in the values, we have: vf^2 = 0^2 + 2 * 9.5 * 57 Simplifying this equation, we get: vf = √(2 * 9.5 * 57). Using a calculator, the final velocity is approximately 27.4 m/s. Therefore, option B is the correct answer.