Question

If a simple pendulum oscillates with an amplitude of 50 mm and a time period of 2 seconds, what is its maximum velocity?

a) 50 mm/s
b) 100 mm/s
c) 25 mm/s
d) 200 mm/s

Answer 1

The maximum velocity of a simple pendulum with an amplitude of 50 mm and a time period of 2 seconds is approximately 0.157 m/s. The answer is not given among options.

Step-by-step explanation:

The maximum velocity of a simple pendulum can be calculated using the formula:

Maximum velocity = Amplitude * angular frequency

The angular frequency can be calculated using the formula:

Angular frequency = 2π / time period

Substituting the given values, we have:

Amplitude = 50 mm
Time period = 2 seconds

Converting the amplitude to meters:

Amplitude = 50 mm = 0.05 m

Calculating the angular frequency:

Angular frequency = 2π / 2 = π rad/s

Calculating the maximum velocity:

Maximum velocity = 0.05 m * π rad/s ≈ 0.157 m/s

Therefore, the maximum velocity of the simple pendulum is approximately 0.157 m/s.

Hence, The answer is not given among options.