Find a recursive formula for the following sequence:4, 11, 25, 53, 109, ...

Haresh Samnani asked May 14, 2023

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Haresh Samnani asked May 14, 2023

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17 votes

Notice the following pattern in the given sequence:

$\begin{gathered} 11=4\cdot2\text{ +3,} \\ 25=11\cdot2+3, \\ 53=25\cdot2+3, \\ 109=53\cdot2+3. \end{gathered}$

Therefore, the n-term of the sequence has the following form:

$a_n=a_{n-1\text{ }}+3.$

Answer:

$a_n=a_{n-1\text{ }}+3.$

Jnbdz answered May 20, 2023

by Jnbdz

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