Question

A little boy pulls a spring with force constant k out a distance s and in so doing, does an amount of work W. By comparison, how much work would he do to pull the spring out a distance

Answer 1

The answer is "
`w'= (w)/(4)`"

Step-by-step explanation:

According to the work-energy theorem:

work = changes in the potential energy

`w= (1)/(2) K S^2-0\\\\w= (1)/(2) K S^2. . . . . . . . . . . (1) \\\\w'= (1)/(2) K (S^2)/(2) -0\\\\w'= (1)/(2) K ((S)/(2))^2\\\\ w'= (1)/(2) K (S^2)/(4) . . . . . . . . . . . (2) \\\\`

by putting the w value in equation 2. so, the value is:

`\boxed{w'= (w)/(4)}`