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(TOLD) Vrot relation to Vref
Vrot = Vref - 6 (appx)

User Wuchang
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1 Answer

6 votes

Final Answer:

According to the given relation, when \(V_{\text{ref}}\) is 10, \(V_{\text{rot}}\) is approximately 4.

Step-by-step explanation:

The information provided suggests a relation between \(V_{\text{rot}}\) (rotational velocity) and \(V_{\text{ref}}\) (reference velocity) in the form of an approximate equation:

\[ V_{\text{rot}} = V_{\text{ref}} - 6 \]

This equation indicates that the rotational velocity (\(V_{\text{rot}}\)) is approximately equal to the reference velocity (\(V_{\text{ref}}\)) minus 6.

If you have specific values for \(V_{\text{ref}}\), you can use this equation to find the corresponding \(V_{\text{rot}}\) by substituting the values into the equation.

For example, if \(V_{\text{ref}}\) is 10, then:

\[ V_{\text{rot}} = 10 - 6 = 4 \]

So, according to the given relation, when \(V_{\text{ref}}\) is 10, \(V_{\text{rot}}\) is approximately 4.

User Andresk
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