Question

Two containers designed to hold water are side by side both in the shape of a cycle see. Container A has a radius of 4 feet and a height of 9 feet. Container B has a radius of 3 feet and height of 11 feet. Container A is full of water and the water is pumped into container B until container B is completely full. After the pumping is complete what is the volume of water remaining in container A to the nearest tenth of a cubic foot

Answer 1

We have to calculate the water remaining in A
after B is complete.
This will be equal to the volume of A minus the
volume of B.
The volume of each cylinder is equal to the area
of the base times the height, so we can calculate
this difference as:
- VA
- VB
V
=1(rA)?hA-T(rB)?hB
V
= 7(4)3 (9)
- 1(3)3 (11)
V
= 7(16) (9) - 1(9)(11)
V= 1447 - 99T
V
= 45 T
V~141.4
Answer: the remaining volume is
approximately 141.4 cubic feet.

Answer 2

We have to calculate the water remaining in A after B is complete.

This will be equal to the volume of A minus the volume of B.

The volume of each cylinder is equal to the area of the base times the height, so we can calculate this difference as:

`\begin{gathered} V=V_A-V_B \\ V=\pi(r_A)^2h_A-\pi(r_B)^2h_B \\ V=\pi(4)^2(9)-\pi(3)^2(11) \\ V=\pi(16)(9)-\pi(9)(11) \\ V=144\pi-99\pi \\ V=45\pi \\ V\approx141.4 \end{gathered}`

Answer: the remaining volume is approximately 141.4 cubic feet.