Final answer:
To measure the distance from a physician's eyes to the examined feature when the power of the eyes is 53.0 D, one would calculate the reciprocal of the power to find the image distance di, resulting in a distance of approximately 18.9 centimeters from the eye.
Step-by-step explanation:
The question relates to calculating the distance from a physician's eyes to the feature being examined based on the power of the physician's eyes. The power of a physician's eyes is given as 53.0 diopters (D). To find the distance for clear vision, where the image must be on the retina, we use the formula P = 1/di + 1/do. Since the power (P) is given, and for close vision do is typically about 25.0 cm, we can rearrange the formula to solve for di (the distance from the eye to the object).
To calculate this, express all distances in meters. Therefore, for distant vision, the object distance do tends towards infinity, which makes the reciprocal term 1/do effectively zero. This simplifies the equation to P = 1/di, which can be further simplified to di = 1/P. Then, you can calculate the distance by taking the reciprocal of the power in diopters, ensuring the power is converted into meters for the calculation. In this case, for a power of 53.0 D, the distance di would be calculated as approximately 1/53 meters, which is about 0.0189 meters or 18.9 centimeters.