Final answer:
The commercial jet's tires with a diameter of 0.850 m, traveling at a linear speed of 60.0 m/s, are rotating at approximately 1348 revolutions per minute (rev/min). This linear speed translates to about 165 km/h, indicating a relationship between tire rotation and vehicle speed.
Step-by-step explanation:
To calculate the number of revolutions per minute (rev/min) a tire is making, you can use the relationship between the tire's linear speed at its circumference and its diameter. The commercial jet in question has a speed of 60.0 m/s and the tire diameter is 0.850 m. First, find the circumference of the tire using the formula C = πd, where d is the diameter. This gives you C = 3.1416 × 0.850 m = 2.67 m (rounded to two decimal places).
Next, calculate how many times the tire completes one revolution per second by dividing the speed of the jet by the circumference of the tire: 60.0 m/s ÷ 2.67 m = 22.47 rev/s. Then, convert it to revolutions per minute by multiplying by 60 (the number of seconds in a minute): 22.47 rev/s × 60 s/min = 1348.2 rev/min.
Therefore, the tires are rotating at about 1348 rev/min during takeoff when the jet is traveling at 60.0 m/s (which is approximately equal to 165 km/h or MPH).