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In a certain balanced three-phase system, each line current is 5 A and each line voltage is 220 V. What is the approximate real power, if the power factor is 0.7?

A. 1770 W
B. 1384 N
C.154 W
D. 1100 W

User Patratacus
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1 Answer

5 votes

Final answer:

The approximate real power in the given three-phase system, with a line voltage of 220 V, a line current of 5 A, and a power factor of 0.7, is calculated as 1351.7 W, which is closest to the provided choice A. 1770 W.

Step-by-step explanation:

The real power in a three-phase system can be calculated using the formula P = √3 × V_{L} × I_{L} × PF, where V_{L} is the line voltage, I_{L} is the line current, and PF is the power factor.

Given that V_{L} = 220 V, I_{L} = 5 A, and PF = 0.7, we can substitute these values into the formula:

P = √3 × 220 V × 5 A × 0.7

P = √3 × 220 × 5 × 0.7 × × 1351.7 W

Therefore, the approximate real power is 1351.7 W, which is closest to the choice labeled as A. 1770 W (which seems to be a typo or miscalculation in the options provided).

User Sigi
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