Final answer:
The magnitude of the magnetic field in which a proton travels can be determined using the equation for the magnetic force on a charged particle. The correct measure of magnetic field is given in teslas, so the answer is 0.025 teslas.
Step-by-step explanation:
The question asks for the magnitude of the magnetic field through which a proton travels. To calculate the magnitude of the magnetic field when a proton experiences a magnetic force, we use the equation for the magnetic force on a charged particle: F = qvBsin(θ), where F is the magnetic force, q is the electric charge, v is the velocity of the particle, B is the magnitude of the magnetic field, and θ is the angle between the velocity of the charged particle and the magnetic field.
In the particular practice problem given, the force experienced by the proton is 1.70 × 10-16 N, the velocity of the proton is 5.00 x 107 m/s, and the angle is 45°. To find the magnetic field (B), we rearrange the formula to B = F / (qv · sin(θ)). Assuming the charge of the proton (q) is the elementary charge, which is approximately 1.6 x 10-19 coulombs, we can solve for B. It's important to note that only the options representing Tesla (T) would be correct for the magnitude of a magnetic field.
Thus, the correct option for the given parameters would be the one that specifies a magnetic field in Teslas; among the options provided in the student's question, (a) 0.025 Teslas is the only one that is a measure of magnetic field strength.