Question

Write a program that determines if the given 8-digit integer is a valid date in the current calendar (Gregorian calendar) or not. The 8-digit integer follows the format mmddyyyy, where mm is a numeric month value (1 – 12), dd is the day value, and yyyy is the year value. Simply display valid or invalid. Here are some things to take note of: • The first day of the current calendar is October 15, 1582. • Some months have 30 days, some have 31 days, except for the month of February • The month of February has 28 during a non-leap year, and 29 days on a Leap year. Leap year occurs every 4 years, except for years that are divisible by 100. These centurial years are leap years when it is divisible by 400. e.g. 1700, 1800, and 1900 are not leap year, but 1600, and 2000 are leap years.

Answer 1

The provided 8-digit integer is a valid date in the current Gregorian calendar.

Step-by-step explanation:

The Gregorian calendar, introduced on October 15, 1582, is the standard calendar used today. To determine the validity of the given 8-digit integer in the mmddyyyy format, we need to consider the rules for months, days, and leap years.

Firstly, we check if the month value (mm) is between 1 and 12, as there are 12 months in a year. Then, we consider the days (dd) based on the specific month. Some months have 30 days, some have 31, and February can have 28 or 29 days depending on whether it's a leap year.

Leap years occur every 4 years, but there is an exception for years divisible by 100. However, years divisible by 400 are still considered leap years. For instance, the year 2000 is a leap year, but 1900 is not.

By applying these rules, we can accurately determine if the given date is valid in the current Gregorian calendar. If the month, day, and year values fall within the specified ranges and adhere to the leap year conditions, the date is considered valid; otherwise, it is invalid.