Final answer:
The maximum tire limit speed for the CRJ 550/700 cannot be determined from the information given. However, using the reference information about takeoff speed and tire diameter, it can be calculated that the tires of a jet traveling at 60.0 m/s with a diameter of 0.850 m are rotating at approximately 1344 revolutions per minute (rev/min).
Step-by-step explanation:
The maximum tire limit speed for the CRJ 550/700 is not provided in the question, so we cannot determine it from the given information. Instead, let's focus on the physics problem presented in the question's reference information.
To find out at how many revolutions per minute (rev/min) the tires of a commercial jet are rotating at takeoff, given that the speed is 60.0 m/s and the tire's diameter is 0.850 m, we can use the formula for the circumference of a circle and the relationship between linear speed and rotational speed.
The circumference C of a tire can be calculated using the formula C = πd, where d is the diameter. For a tire diameter of 0.850 m, the circumference C = π × 0.850 m. Each rotation of the tire covers this distance. To find the number of rotations per second, we divide the linear speed by the circumference of the tire:
Rotations per second = Speed / Circumference
Using the given speed of 60.0 m/s:
Rotations per second = 60.0 m/s / (π × 0.850 m) ≈ 22.4 rev/s
To convert this to revolutions per minute (rev/min), we multiply by 60 seconds per minute:
Revolutions per minute = 22.4 rev/s × 60 s/min ≈ 1344 rev/min
Therefore, at takeoff, the tires of the commercial jet are rotating at approximately 1344 rev/min.