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You spin a spinner numbered from 1 to 8 twice​. Find the probability of getting a 1 on the first spin and a 2 on the second spin.

User Simanas
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1 Answer

9 votes

Answer:


Probability = (1)/(64)

Explanation:

The sample space of the spinner is:


Sample\ Space = \{1,2,3,4,5,6,7,8\}

So:


n(S)= 8

All of which have the same probability.

Required

Determine the probability of 1, then 2 when spin twice

The probability of the first being 1 is:


P(1)= n(1)/n(S)


P(1)= 1/8

The probability of the second being 2 is:


P(2)= n(2)/n(S)


P(2)= 1/8

So, the required probability is:


Probability = P(1) * P(2)


Probability =1/8* 1/8


Probability = (1)/(64)

User Kerrith
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