Question

If ABCD is dilated by a factor of 2, thecoordinate of B' would be:543С2B1-8 -7-6-5-4-3-2-1 012.34567891011-1A-2D-3B' = ([?], [ ]=4Cotor

Answer 1

We have a figure ABCD that is dilated by a factor of 2.

We have to find the coordinate of the image point B'.

If the center of dilation is the origin (0,0) and the factor is k = 2, we can write the rule:

`(x,y)\longrightarrow(2x,2y)`

Then, for B(-1,1), we will get:

`B=(-1,1)\longrightarrow B^(\prime)=(2\cdot(-1),2\cdot1)=(-2,2)`

Answer: B' = (-2,2)