120k views
11 votes
PLEASE HELP!!!
I need help with this math homework

PLEASE HELP!!! I need help with this math homework-example-1
User Sshet
by
8.8k points

1 Answer

0 votes

9514 1404 393

Answer:

  • x = 14√2
  • y = 14
  • z = 14√3

Explanation:

These are two "special triangles." The ratios of side lengths are numbers not difficult to remember. They can save a lot of work in problems like this.

Ratio of side lengths in 45°-45°-90° isosceles right triangle: 1 : 1 : √2.

Ratio of side lengths in 30°-60°-90° right triangle: 1 : √3 : 2.

__

The side marked x has the same length as the side marked 14√2.

x = 14√2

The unmarked hypotenuse of both triangles is √2 times the marked side length, so is (14√2)(√2) = 28.

The side marked y is half the length of the hypotenuse of that triangles so is ...

y = 28/2

y = 14

And the side marked z is √3 times the short side of the 30°-60°-90° triangle, so is ...

z = 14√3

_____

Alternate solution

The mnemonic SOH CAH TOA can help you remember trig relationships. Here, 14√2 is opposite the given 45° angle, and x is adjacent. The trig relation is ...

Tan = Opposite/Adjacent

tan(45°) = 14√2/x

x = 14√2/tan(45°) = 14√2

__

To find y or z, we need to know the length of the hypotenuse in the 45° triangle. The given side is opposite the angle, so we can use the sine relation:

Sin = Opposite/Hypotenuse

hypotenuse = 14√2/sin(45°) = 28

Now, we can find y and z:

sin(30°) = y/hypotenuse

y = (28)sin(30°) = 14

cos(30°) = z/hypotenuse

z = (28)cos(30°) = 14√3

User Antrromet
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories