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12^½/3^³/²


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12^½/3^³/² plsss help fast​-example-1
User TJR
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1 Answer

2 votes

Answer:


(2)/(3)

Explanation:

Given rational expression:


(12^(\frac12))/(3^(\frac32))

To evaluate the given rational expression, begin by rewriting 12 as the product of its prime factors:


(\left(2^2 * 3\right)^(\frac12))/(3^(\frac32))

Now, apply the power of a product rule of exponents to the numerator:


(\left(2^2\right)^(\frac12) * 3^(\frac12))/(3^(\frac32))

Apply the power of a power rule of exponents to
\left(2^2\right)^(\frac12):


(2^(2* \frac12) * 3^(\frac12))/(3^(\frac32))


(2^(\frac22) * 3^(\frac12))/(3^(\frac32))


(2^(1) * 3^(\frac12))/(3^(\frac32))


(2* 3^(\frac12))/(3^(\frac32))

Rewrite the exponent in the denominator as the sum of 1 and 1/2:


(2* 3^(\frac12))/(3^(1+\frac12))

Apply the product rule of exponents to the exponent in the denominator:


(2* 3^(\frac12))/(3^(1)* 3^(\frac12))


(2* 3^(\frac12))/(3* 3^(\frac12))

Cancel the common factor
3^(\frac12):


(2* \diagup\!\!\!\!\!3^(\frac12))/(3* \diagup\!\!\!\!\!3^(\frac12))


(2)/(3)

Therefore, the evaluation of the given rational expression is:


\Large\boxed{\boxed{(2)/(3)}}


\hrulefill


\boxed{\begin{array}{rl}\underline{\sf Exponent\;Rules}\\\\\sf Power\;of\;a\;Product:&(ab)^m=a^mb^m\\\\\sf Power\;of\;a\;Power:&(a^m)^n=a^(mn)\\\\\sf Product:&a^m * a^n=a^(m+n)\\\\\end{array}}

User Aakash Handa
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