There are no dimensions of two gardens each having a perimeter of 30 meters and where the area of the garden A is 4 times greater than the area of garden B.
Working out the dimensions of each garden with lenght and weight
From the question, we have the following parameters that can be used in our computation:
Both perimeter = 30 m
Area A = 4 * Area B
Let x be the length of the smaller garden and y be the width of the smaller garden.
So, the length of the larger garden is 4x and the width of the larger garden is 4y.
Using the permeter, we have
2x + 2y = 30
2(4x) + 2(4y) = 30
Simplifying the second equation, we get:
4x + 4y = 15
Using substitution, we can solve for y in terms of x:
y = 6 - x
Substituting this expression for y in the first equation, we get:
4x + 4(6 - x) = 15
Expanding, we get:
4x + 24 - 4x = 15
Simplifying, we get:
24 = 15
This is not true, so there is no solution for x and y that satisfies both of the original equations.