The coordinates of the image of trapezoid JKLM are J'(x, y) = (1, 3), K'(x, y) = (4, 4), L'(x, y) = (6, 0) and M'(x, y) = (- 1, - 3).
How to find the coordinates of the image of a trapezoid
Herein we find the coordinates of the vertices of trapezoid JKLM, whose image is determined by means of a rigid transformation known as translation, whose formula is:
P'(x, y) = P(x, y) + T(x, y)
Where:
- P(x, y) - Original point
- T(x, y) - Translation vector
- P'(x, y) - Resulting point
If we know that J(x, y) = (- 6, 6), K(x, y) = (- 3, 7), L(x, y) = (- 1, 3), M(x, y) = (- 8, 0) and T(x, y) = (7, - 3), then the coordinates of the image are:
J'(x, y) = (- 6, 6) + (7, - 3)
J'(x, y) = (1, 3)
K'(x, y) = (- 3, 7) +(7, - 3)
K'(x, y) = (4, 4)
L'(x, y) = (- 1, 3) + (7, - 3)
L'(x, y) = (6, 0)
M'(x, y) = (- 8, 0) + (7, - 3)
M'(x, y) = (- 1, - 3)