Question

A ball is thrown from a height of 80 feet with an initial downward velocity of 4/fts. The ball's height h (in feet) after t seconds is given by the following.

h=80-4t-16t^2

Answer 1

The equation (h = 80 - 4t - 16t^2) represents the height (h) of the ball as a function of time (t), where:(h) is the height in feet,(t) is the time in seconds.The equation is in the form of (h(t) = at^2 + bt + c), where (a), (b), and (c) are coefficients. In this case, (a = -16), (b = -4), and (c = 80).The negative coefficient of (t^2) indicates that the ball is undergoing free fall with an initial downward velocity.