Question

Michael hires a cab that charges a fare of $0.50 per mile, plus an initial charge of $2. Jason hires a cab that charges a fare of $0.50 per mile, plus an initial charge of $3.50. At how many miles will the fares paid by Michael and Jason become equal? A. The fares paid by Michael and Jason will become equal at 1.5 miles. B. The fares paid by Michael and Jason will become equal at 6 miles. C. The fares paid by Michael and Jason will be equal at every mile. D. The fares paid by Michael and Jason will never be equal.

Answer 1

below

Explanation:

So to find the number of miles at which the fares paid by Michael and Jason become equal, we can set up an equation.

I'm going to represent the number of miles by x.

The fare paid by Michael can be calculated as: $2 (initial charge) + $0.50 (fare per mile) * x (number of miles).

So, the fare paid by Michael is 2 + 0.50x.

Also, the fare paid by Jason can be calculated as: $3.50 (initial charge) + $0.50 (fare per mile) * x (number of miles).

So, the fare paid by Jason is 3.50 + 0.50x.

To find the number of miles at which the fares paid by Michael and Jason are equal, we set up the equation:

2 + 0.50x = 3.50 + 0.50x

I'll simplify the equation by subtracting 0.50x from both sides:

2 = 3.50

because 2 is not equal to 3.50, the equation has no solution.

Therefore, the fares paid by Michael and Jason will never be equal. The correct answer is D: The fares paid by Michael and Jason will never be equal.


That will be $10
Tip....
10% 25% 50% 100%