Question

A sulfur containing compound is treated chemically to convert all its sulfur into barium sulfate. A 8.19 mg sample of the compound gave 5.46 mg barium sulfate. a) What is the percentage of sulfur in the compound

Answer 1

The percentage of sulfur in the compound is 0.90%.

Step-by-step explanation:

To find the percentage of sulfur in the compound, we need to calculate the mass of sulfur in the sample and divide it by the mass of the compound multiplied by 100.

Given that 8.19 mg of the compound gave 5.46 mg of barium sulfate, we can calculate the mass of sulfur in the compound:

(5.46 mg of barium sulfate) * (1 mol of sulfur / 233.38 g of barium sulfate) * (32.07 g of sulfur / 1 mol of sulfur) = 0.0738 mg of sulfur.

Finally, we can calculate the percentage of sulfur in the compound:

(0.0738 mg of sulfur / 8.19 mg of the compound) * 100 = 0.90%