Question

Please help i need to get this turned in tonight


Find the value of y.

Answer 1

`\sf\\3y^o\ and\ (y+20)^o \textsf{ here are cointerior angles, hence their sum is }180^o.\\ \therefore\ 3y+y+20^o=180^o\\or,\ 4y=160^o\\or,\ y=40^o`

`\sf\\\textsf{2x and (x-12)}^o\textsf{ are also cointerior angles.}\\\therefore\ 2x+x-12^o=180^o\\or,\ 3x=192^o\\or,\ x=64^o`