Question

How can you use a logarithmic function to solve 8^x=32,768

Answer 1

Explanation:

`\boxed{let\ a^b=c,\ then\ log_a(c)=b}`

`for\ 8^x=32768,\ then\ log_8(32768)=x`

`x=(log\ 32768)/(log\ 8)`

`x=(log(2^(15)))/(log(2^3))`

`x=(15(log(2)))/(3(log(2)))`

`x=5`