Answer:
Graph D.
Explanation:
From equation (1):
=> 6 (n-1) < 3
=> (6n - 6) < 3
=> 6n < 9
=> n < 9/6
=> n < (3*3)/(3*2)
=> n < (3/2) * (3/3) => n < (3/2) * 1/1
=> n < 3/2
=> n < (2/2) + (1/2)
=> n < 1 + 0.5
=> n < 1.5
Now for equation 2,
=> 2(n+1)>0
=>2n + 2 > 0
=> 2n > -2
=> n > -2/2
=> n> -1/1
=> n > -1
Now, a solution to BOTH of these equations means they fall between these intervals
=> n<1.5 & n>-1
=> -1<n<1.5
So for the value of n has to lie between -1.0 and 1.5 for it to be a solution to BOTH of these equations.