Question

5.

The weight of a rectangular block of metal varies jointly as its length, width and thickness.
If the weight of a 13 by 8 by 6 dm block of aluminum is 18.2 kg, find the weight of a 16 by
10 by 4 dm block of aluminum.
NEED STEP-BY-STEP ANSWER
Plssss

Answer 1

The weight of the second block is approximately 10.32 kg.

Step-by-step explanation:

To solve this problem, we can use the formula for joint variation:

Weight = k * length * width * thickness

First, we need to find the value of k by plugging in the given values of weight, length, width, and thickness:

18.2 kg = k * 13 dm * 8 dm * 6 dm

Solving for k:

k = 18.2 kg / (13 dm * 8 dm * 6 dm)

Now that we have the value of k, we can find the weight of the second block using the new values of length, width, and thickness:

Weight = k * 16 dm * 10 dm * 4 dm

Plugging in the values and solving:

Weight = (18.2 kg / (13 dm * 8 dm * 6 dm)) * 16 dm * 10 dm * 4 dm

Weight = 10.32 kg