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what is the boiling point of a solution made by dissolving 10.0 g sucrose in 500.0 g carbon tetrachloride

User Dray
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1 Answer

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Final answer:

The boiling point of the solution will be the same as that of the pure solvent, which is 76.8 °C.

Step-by-step explanation:

The boiling point of a solution depends on the concentration of the solute in the solvent. In this case, the solute is 10.0 g of sucrose and the solvent is 500.0 g of carbon tetrachloride. Sucrose is a nonvolatile solute, meaning it does not evaporate easily.

The boiling point elevation constant for carbon tetrachloride is 0.0 °C/m. Since sucrose does not affect the boiling point of carbon tetrachloride, the boiling point of the solution will be the same as that of the pure solvent, which is 76.8 °C.

User FishBowlGuy
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