Question

Given the function f(x)= 7lx-4l, calculate the following values:F(0)=F(2)=F(-2)=F(x+1)=F(x^2+2)=

Answer 1

As given by the question

There is given that the function

`f(x)=7\lvert x-4\rvert`

Now,

First find the value of f(0):

Then, put the value of 0 for x into the given function.

Now,

`\begin{gathered} f(x)=7\lvert x-4\rvert \\ f(0)=7\lvert0-4\rvert \\ f(0)=7\lvert-4\rvert \\ f(0)=7\cdot4 \\ f(0)=28 \end{gathered}`

Then,

`\begin{gathered} f(x)=7\lvert x-4\rvert \\ f(2)=7\lvert2-4\rvert \\ f(2)=7\lvert-2\rvert \\ f(2)=7\cdot2 \\ f(2)=14 \end{gathered}`

Then,

`\begin{gathered} f(x)=7\lvert x-4\rvert \\ f(-2)=7\lvert-2-4\rvert \\ f(-2)=7\lvert-6\rvert \\ f(-2)=7\cdot6 \\ f(-2)=42 \end{gathered}`

Then,

`\begin{gathered} f(x)=7\lvert x-4\rvert \\ f(x)=7\lvert x+1-4\rvert \\ f(x)=7\lvert x+1-4\rvert \\ f(x)=7\lvert x-3\rvert \end{gathered}`

And,

`\begin{gathered} f(x)=7\lvert x-4\rvert \\ f(x^2+2)=7\lvert x^2+2-4\rvert \\ f(x^2+2)=7\lvert x^2-2\rvert \end{gathered}`