1 Answer

Bojan Dimovski · Answer 1 · 2024-09-12T22:42:47+0000

Answer:

${ log }^(2) 8 - { log}^(2) 125 = {(3 log(2)) }^(2) - {(3 log(5) )}^(2) =$

(3log(2) + (3log(5))(3log(2) - 3log(5)) =

(3log10)(3log(0.4)) = 9log10log(0.4)

log_(0.4)(4) + 2 log_(0.4)(5) =

log_(0.4)(4) + log_(0.4)(25) = log_(0.4)(100) = ( log(100) )/( log(0.4) )

(9log(10)log(0.4))(2log(10)/log(0.4)) =

18(log(10))²

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