Question

8 Xsquared Potato Crisps runs a promotion

for a week. In 0.01% of the hundreds of
thousands of bags produced there are gold
tickets for a round-the-world trip. Let B
represent the number of bags of crisps
opened until a gold ticket is found.
a Find P(B= 1), P(B= 2) and P(B = 3).

Answer 1

To find the probabilities P(B = 1), P(B = 2), and P(B = 3), we can use the geometric probability formula.

Step-by-step explanation:

To find the probabilities P(B = 1), P(B = 2), and P(B = 3), we can use the geometric probability formula. The probability of getting a gold ticket in the first bag is 0.01% or 0.0001. So, P(B = 1) = 0.0001.

For P(B = 2), the probability of not getting a gold ticket in the first bag is 1 - 0.0001 = 0.9999. The probability of getting a gold ticket in the second bag is then 0.0001. So, P(B = 2) = 0.9999 * 0.0001 = 0.00009999.

Similarly, for P(B = 3), the probability of not getting a gold ticket in the first two bags is (1 - 0.0001)^2 = 0.9999 * 0.9999. The probability of getting a gold ticket in the third bag is 0.0001. So, P(B = 3) = 0.9999 * 0.9999 * 0.0001

= 0.000099989.