The voltage across the capacitor is 388.34 V
The voltage across the inductor is 383.3 V.
How to calculate the voltage across the capacitor and inductor?
The voltage readings across the capacitance and inductance is calculated by applying the following formula as shown below;
The capacitive reactance;
Xc = 1/2πfc
where;
- f is the frequency
- c is the capacitance
Xc = 1 / (2π x 1000 x 0.5 x 10⁻⁶)
Xc = 318.31 ohms
The inductive reactance is calculated as;
Xl = 2πfL
Xl = 2π x 1000 x 0.05
Xl = 314.16 ohms
The impedance of the circuit is calculated as;
Z = √[(Xc - Xl)² + R²]
Z = √[(318.31 - 314.16)² + 20²]
Z = 20.43 ohms
The current in the circuit is;
I = V/Z
I = 25 V / 20.43
I = 1.22 A
The voltage across the capacitor is;
Vc = 1.22 A x 318.31
Vc = 388.34 V
The voltage across the inductor is;
Vl = 1.22 A x 314.16
Vl = 383.3 V