Question

a body is subjected to two normal stresses 20 kn/m2 (tensile) and 10 kn/m2 (compressive) acting perpendicular to each other. the maximum shear stress is

Answer 1

The maximum shear stress can be calculated using the formula σmax = √(σx^2 + σy^2), where σx is the tensile stress and σy is the compressive stress.

Step-by-step explanation:

The maximum shear stress in this case can be calculated using the formula:

σmax = √(σx2 + σy2)

where σx = 20 kN/m² (tensile stress) and σy = 10 kN/m² (compressive stress).

Plugging in the values, we get:

σmax = √((20 kN/m²)2 + (10 kN/m²)2)

σmax = √(400 kN/m² + 100 kN/m²)

σmax = √(500 kN/m²)

σmax ≈ 22.36 kN/m²