Question

how many extractions are required for 99% removal of zinc from the aqueous phase at the ph used in part iv of this experiment?

Answer 1

The number of extractions required for 99% removal of zinc from the aqueous phase depends on the distribution coefficient (Kd) and the efficiency of each extraction step. Without specific values for these parameters, a precise answer cannot be determined.

Step-by-step explanation:

In solvent extraction processes, the distribution coefficient (Kd) represents the equilibrium distribution of a solute between two immiscible phases (aqueous and organic). The number of extractions needed for a certain percentage removal can be estimated using the formula:

`\[ \text{Extraction Efficiency} = \left(1 - \frac{1}{{\text{Kd}}}\right)^{\text{Number of Extractions}} \]`

Given that the desired removal is 99%, the equation becomes:

`\[ 0.99 = \left(1 - \frac{1}{{\text{Kd}}}\right)^{\text{Number of Extractions}} \]`

However, without the specific value of the distribution coefficient (Kd) at the given pH, it's not possible to calculate the exact number of extractions required. The pH can significantly influence the distribution of a metal ion between phases, making it crucial information for accurate calculations. Experimental data or additional details about the system would be necessary to determine the values needed for the calculation.