Question

A ring rotates such that its angular acceleration a is given as a = -3√. If the initial velocity of the disc is 16 rad/s, find the time taken (in s)

Answer 1

The time taken for the ring to come to a stop is approximately 7.11 seconds.

Step-by-step explanation:

To find the time taken for the ring to come to a stop, we can use the equation ε = εo + αt, where ε is the final angular velocity, εo is the initial angular velocity, α is the angular acceleration, and t is the time taken.

In this case, ε = 0, εo = 16 rad/s, and α = -3√. Plugging in the values, we get 0 = 16 - 3√t.

Solving for t, we find t = 64/9 s, which is approximately 7.11 seconds.