The average translational kinetic energy of an oxygen molecule in a 5 litre vessel at a pressure of 8 atm and 0.00 °C is 8.4 x 10⁻¹⁴ J. Option A is correct.
The average translational kinetic energy of a molecule can be calculated using the formula: K.E. = (3/2) kT, where k is the Boltzmann constant and T is the temperature in kelvin. To calculate the average translational kinetic energy of an oxygen molecule, we need to convert the temperature from degrees Celsius to kelvin by adding 273.15.
Given that the pressure is 8 atm and the temperature is 0.00 °C, the average translational kinetic energy of an oxygen molecule is:
K.E. = (3/2) x (1.38 x 10⁻²³ J/K) x (273.15 K) = 8.4 x 10⁻¹⁴ J
Hence, A. is the correct option.
--The given question is incomplete, the complete question is
"A 5 liter vessel contains 2 mole of oxygen gas at a pressure of 8 atm. The average translational kinetic energy of an oxygen molecule under this condition is (a) 8.4 x 10-14 J (b) 4.98 x 10-21 J (c) 7.4 x 10-16 J (d) 4.2 x 10-23 J."--