To calculate the molar mass of the acid, you can use stoichiometry and the given information. First, calculate the number of moles of KOH used, then find the number of moles of the acid, and finally divide the mass of the acid by the number of moles to find the molar mass. Therefore, the molar mass of the acid is 118.21 g/mol.
To calculate the molar mass of the acid, we need to use the concept of stoichiometry and the given information. First, we calculate the number of moles of KOH used in the reaction:
(0.02256 L)(0.09477 mol/L) = 0.00213657 mol KOH
Now, we can use the stoichiometric ratio between the acid and KOH to find the number of moles of the acid:
(0.00213657 mol KOH)(1 mol acid / 1 mol KOH) = 0.00213657 mol acid
Finally, to calculate the molar mass, we divide the mass of the acid by the number of moles:
Molar mass = 0.2527 g / 0.00213657 mol = 118.21 g/mol
--The given question is incomplete, the complete question is
"A 0.2527g Sample Of A Monoprotic Acid Neutralizes 22.56mL Of A 0.09477M KOH Solution. Calculate The Molar Mass Of The Acid. Round Your Answer To 4 Significant Digits."--