Final Answer:
The cell potential for the reaction between Ca and Zn is 3.63 V.
Step-by-step explanation:
The cell potential (E) for a galvanic cell can be calculated using the following equation:
E = E_cathode - E_anode
where:
E is the cell potential (V)
E_cathode is the standard reduction potential of the cathode (V)
E_anode is the standard reduction potential of the anode (V)
In this case, the cathode is the Zn electrode and the anode is the Ca electrode. The standard reduction potential of Zn is -0.76 V and the standard reduction potential of Ca is 2.87 V. Therefore, the cell potential is:
E = 2.87 V - (-0.76 V) = 3.63 V
Therefore, the cell potential for the reaction between Ca and Zn is 3.63 V.