Answer:
1) B(6, 2)
2) C(1, 2)
3) Translation of 6 units left and 7 units down.
4) (x, y) → (x - 6, y - 7)
5) P' = (-2, 4)
6) (x, y) → (y, x)
Explanation:
Question 1
ABC is a right triangle with vertices A(6, 7), B(m, n) and C(1, 2). AB is a vertical line and BC is a horizontal line. Therefore, the x-coordinate of B is the same as the x-coordinate of A, and the y-coordinate of B is the same is the y-coordinate of C. So, the coordinates of point B are (6, 2).
Question 2
From observation of the graph, we can see that the coordinates of C are (1, 2).
Question 3
To determine the transformation that maps triangle ABC to triangle A'B'C', we can examine the coordinates of points A and A'. Point A is located at (6, 7), and point A' is located at the origin (0, 0). Therefore, for point A to be transformed to point A', we need to translate the point 6 units left and 7 units down.
Question 4
Translating a point 6 units left means subtracting 6 units from its x-coordinate. Translating a point 7 units down means subtracting 7 units from its y-coordinate. Therefore, the mapping rule that transforms ABC to A'B'C' is:

Question 5
The location of point P is (4, -2). If it is reflected about the line y = x, the new coordinates can be found by swapping the x and y coordinates. Therefore, the reflection of point P across the line y = x is given by the coordinates P' = (-2, 4).
Question 6
The algebraic rule for a reflection about the line y = x can be expressed as:

This rule states that the reflected point is obtained by swapping the x- and y-coordinates of the original point.