Question

a container holds 0.456 m3 of oxygen at an absolute pressure of 3.94 atm. a valve is opened, allowing the gas to drive a piston, increasing the volume of the gas until the pressure drops to 1.00 atm. if the temperature remains constant, what new volume does the gas occupy? m3

Answer 1

The new volume of the gas is 1.79 m³.

Step-by-step explanation:

Boyle's law states that the pressure of a gas is inversely proportional to its volume at constant temperature. This can be expressed mathematically as:

P1V1 = P2V2

where:

P1 is the initial pressure

V1 is the initial volume

P2 is the final pressure

V2 is the final volume

We are given that the initial pressure is 3.94 atm, the initial volume is 0.456 m³, and the final pressure is 1.00 atm. We need to solve for the final volume, V2.

Plugging in the values we know, we get:

(3.94 atm)(0.456 m³) = (1.00 atm)(V2)

Solving for V2, we get:

V2 = (3.94 atm)(0.456 m³) / (1.00 atm) = 1.79 m³

Therefore, the new volume of the gas is 1.79 m³.