Question

treating the ladder as a uniform rod of length 3.56 m and mass 10.3 kg , find the torque the person must exert on the ladder to give it an angular acceleration of 0.353 rad/s2 .

Answer 1

To find the torque the person must exert on the ladder, you can use the equation τ = Iα. The moment of inertia of the ladder is determined using the formula I = (1/3)mL². By substituting the given values into the torque equation, the required torque is found to be 15.33235472 N·m.

Step-by-step explanation:

To find the torque the person must exert on the ladder, we can use the equation τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration.

First, we need to calculate the moment of inertia of the ladder. Since the ladder is treated as a uniform rod, we can use the formula I = (1/3)mL², where m is the mass of the ladder and L is the length of the ladder.

Plugging in the values, we have I = (1/3)(10.3 kg)(3.56 m)² = 43.44224 kg·m².

Now, we can substitute the values into the torque equation:

τ = (43.44224 kg·m²)(0.353 rad/s²) = 15.33235472 N·m.

Therefore, the person must exert a torque of 15.33235472 N·m on the ladder to give it an angular acceleration of 0.353 rad/s².