14.5k views
4 votes
Keisha decides to roll a number cube until she gets a 6. Let X = the number of rolls until she rolls a 6.

What is the mean of X?
What is the standard deviation of X?

1 Answer

7 votes

Explanation:

The mean of X, which represents the average number of rolls until Keisha gets a 6, can be calculated using the formula for the mean of a geometric distribution:

Mean = 1/p

Where p is the probability of rolling a 6 on a single roll of the number cube. Since there is a 1/6 probability of rolling a 6 on each roll, the mean can be calculated as:

Mean = 1/(1/6) = 6

So, the mean of X is 6.

The standard deviation of X, which measures the spread or variability of the number of rolls until Keisha gets a 6, can be calculated using the formula for the standard deviation of a geometric distribution:

Standard deviation = sqrt((1-p)/p^2)

Where p is again the probability of rolling a 6 on a single roll. Using the same probability of 1/6, the standard deviation can be calculated as:

Standard deviation = sqrt((1-(1/6))/(1/6)^2) = sqrt(5/36) ≈ 0.6455

So, the standard deviation of X is approximately 0.6455.

User Juanreyesv
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories