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Write with structural formulas and cofactors the committed step of glycolysis.

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Final answer:

The committed step of glycolysis is the conversion of fructose-6-phosphate to fructose-1,6-bisphosphate by the enzyme phosphofructokinase.

Step-by-step explanation:

The committed step of glycolysis is the conversion of fructose-6-phosphate to fructose-1,6-bisphosphate, catalyzed by the enzyme phosphofructokinase-1 (PF K-1). This reaction is crucial in regulating the glycolytic pathway. The structural formula of fructose-6-phosphate is
\rm HOCH_2(CHOH)_3PO_4, and fructose-1,6-bisphosphate is
\rm HOCH_2(CHOH)_3PO_4(CHOH)_2PO_4.

The enzyme PF K-1 requires ATP as a cofactor for this reaction. The committed step is highly regulated, and the phosphorylation of fructose-6-phosphate is an irreversible process, committing the substrate to further metabolism in glycolysis. This regulation ensures control over the glycolytic pathway and links cellular energy needs to metabolic activity.

User Dave Ward
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