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25 votes
25 votes
A hair dryer draws 6.0 A when plugged into a 120-V line. (a) What is its resistance? (b) How much charge passes through it in 15 min?

User Danyim
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1 Answer

7 votes
7 votes

We will have the following:

a)


R=(120V)/(6A)\Rightarrow R=20\Omega

b)


Q=(6A)(15min\ast(60s)/(1min))\Rightarrow Q=5400W

So, the charge is 5400 W in 15 minutes.

User RishiKesh Pathak
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