Final Answer:
To prepare 4 ounces of a 20% sucrose solution, you would need approximately 23.66 grams of sucrose. This calculation is based on the formula: Amount of Sucrose (grams) = (Percentage of Sucrose/100) × Total Solution Volume (milliliters).
Step-by-step explanation:
To determine the amount of sucrose needed to prepare 4 ounces of a 20% sucrose solution, you can use the formula:
\[ \text{Amount of Sucrose (grams)} = \left( \frac{\text{Percentage of Sucrose}}{100} \right) \times \text{Total Solution Volume (milliliters)} \]
In this case, the percentage of sucrose is 20%, and the total solution volume is 4 ounces. To make the calculation, we need to convert ounces to milliliters, as grams and milliliters are more compatible units for this calculation.
1 ounce is approximately equal to 29.5735 milliliters. Therefore, 4 ounces is approximately \(4 \times 29.5735 = 118.294\, \text{milliliters}\).
Now, apply the formula:
\[ \text{Amount of Sucrose (grams)} = \left( \frac{20}{100} \right) \times 118.294 \]
\[ \text{Amount of Sucrose (grams)} = 0.2 \times 118.294 \]
\[ \text{Amount of Sucrose (grams)} = 23.6588 \, \text{grams} \]
So, approximately 23.66 grams of sucrose are needed to prepare 4 ounces of a 20% sucrose solution.