Question

If the average of x, y, and 4 is 24, what is the average of x+6, y-3, and 10? • 12 18 • 24 • 27

Answer 1

To find the average of x+6, y-3, and 10, we use the known average of x, y, and 4, which is 24, to determine their sum (72) and modify it based on the changes to the numbers, resulting in a new average of 27.

Step-by-step explanation:

The provided question asks to find the average of a new set of numbers, given the average of a previous set. First, we start by finding the sum of the original three numbers based on their average. Given that the average of x, y, and 4 is 24, we can set up the following equation: (x + y + 4) / 3 = 24. By multiplying both sides by 3, we find the sum of x, y, and 4 is 72.

Next, we apply this sum to the new set of numbers to find their average: (x+6), (y-3), and 10. The sum of the new set is (x + 6) + (y - 3) + 10. Substituting in the sum we found earlier, 72, for (x + y + 4), we get the new sum as 72 + 6 - 3 + 6 = 81. Finally, to find the new average, we divide 81 by 3, which gives us 27.

Therefore, the average of x+6, y-3, and 10 is 27.

Answer 2

27

Step-by-step explanation:

recall that average is equal to the sum/number of values.

so, we have

`24 = (x + y + 4)/(3)`

multiplying both sides by 3 gives

`72 = x + y + 4`

and subtracting both sides with 4 gives

`x + y = 68`

next, we are to find the average of x+6, y-3 and 10.

the sum of the three is:

`x + 6 + y - 3 + 10 \\ = (x + y) + 13 \\ = 68 + 13 \\ = 81`

so, the sum is 81. the average would be 81 / 3 = 27, as we have 3 values. therefore, our answer is 27.