Final answer:
To find the volume of a gas at standard pressure when given its volume at another pressure, Boyle's law is used. By applying the formula P1V1 = P2V2 and substituting the known values, the volume of gas at standard pressure is found to be approximately 4.87 liters.
Step-by-step explanation:
The student is asking to find the volume of gas at standard pressure given that its volume is 5 liters at 740 mmHg pressure. To solve this problem, we can use Boyle's law, which states that the pressure of a gas is inversely proportional to its volume when the temperature and the amount of gas are held constant. Standard pressure is defined as 1 atm, which is equivalent to 760 mmHg.
The formula for Boyle's law is P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume. So, the calculation would be:
- P1 = 740 mmHg
- V1 = 5 L
- P2 = 760 mmHg (standard pressure)
- V2 = ?
When we rearrange the formula to solve for V2, we get V2 = P1V1 / P2. Substituting in the known values:
V2 = (740 mmHg x 5 L) / 760 mmHg = 4.87 L
Therefore, the volume of gas at standard pressure (760 mmHg) would be approximately 4.87 liters.