Final answer:
The total number of alleles A is 55, leading to a frequency of 55% since there are 100 alleles in total in the sample population. The correct option is A.
Step-by-step explanation:
10 individuals are homozygous for the recessive allele "a."
15 individuals are homozygous for the dominant allele "A."
25 individuals are heterozygous.
Each individual has two alleles, so in the population of 50 individuals, there are a total of 100 alleles.
From the homozygous "a" individuals, there are 10 individuals * 2 alleles = 20 "a" alleles.
From the homozygous "A" individuals, there are 15 individuals * 2 alleles = 30 "A" alleles.
From the heterozygous individuals, there are 25 individuals * 1 allele = 25 "A" alleles (since they have one "A" allele each).
Total number of "A" alleles = 30 + 25 = 55 alleles
Frequency of allele A = (Total number of "A" alleles) / (Total number of alleles)
Frequency of allele A = 55 alleles / 100 alleles = 0.55
Converting this to a percentage: 0.55 × 100 = 55%
Therefore, the frequency of allele A in the population is 55%. The answer is option A.