Final Answer:
False. A section of DNA with the sequence TTTTTTTT would not be expected to be more thermally stable than a section with GGGGGGGG.
Step-by-step explanation:
The stability of DNA is influenced by the presence of complementary base pairs and their associated hydrogen bonding. In DNA, adenine (A) pairs with thymine (T), forming two hydrogen bonds, while guanine (G) pairs with cytosine (C), forming three hydrogen bonds.
The number of hydrogen bonds contributes to the overall stability of the DNA structure. A section with a higher content of G-C pairs is generally more stable than a section with A-T pairs due to the stronger G-C hydrogen bonds.
Now, examining the provided sequences, TTTTTTTT and GGGGGGGG, it's evident that T pairs with A and G pairs with C. Both sequences have the same number of base pairs, but the GGGGGGGG sequence forms more hydrogen bonds due to the G-C pairs. Specifically, the GGGGGGGG sequence would form 7 hydrogen bonds (3 for each G-C pair), while the TTTTTTTT sequence would form only 7 hydrogen bonds (2 for each T-A pair). Therefore, the G-rich sequence is expected to be more thermally stable, contrary to the initial statement.