Question

A chemical reaction occurring in a cylinder equipped with a moveable piston produces 0.51 mol of a gaseous product. If the cylinder contained 0.11 mol of gas before the reaction and had an initial volume of 2.3 L, what was its volume after the reaction? A. 1.3 L B. 2.6 L C. 3.9 L D. 5.2 L

Answer 1

The volume of the cylinder after the reaction is approximately 10.59 L.

Explanation:

To solve this question, we can use the concept of the ideal gas law, which states that the number of moles of gas is directly proportional to the volume of the gas at constant temperature and pressure.

Given that the initial volume of the gas is 2.3 L and the initial number of moles is 0.11 mol, we can set up a proportion:

(initial volume)/(initial moles) = (final volume)/(final moles)

Substituting the given values:

2.3 L / 0.11 mol = (final volume) / 0.51 mol

Simplifying the equation:

(2.3 L * 0.51 mol) / 0.11 mol = final volume

Final volume = 10.59 L

Therefore,

The volume of the cylinder after the reaction is approximately 10.59 L.