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A 750-turn solenoid, 29 cm long, has a diameter of 2.5 cm. An 18-turn coil is wound tightly around the center of the solenoid. a) What is the magnetic field inside the solenoid? b) What is the total magnetic flux through the solenoid?

User Ajay Mehta
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Final answer:

The magnetic field inside a solenoid is calculated using Ampere's Law, and the total magnetic flux is the product of the magnetic field and the solenoid's cross-sectional area.

Step-by-step explanation:

Magnetic Field Inside a Solenoid

To find the magnetic field inside a solenoid, we can use Ampere's Law. For an ideal solenoid, this is given by B = μ_0 * (n * I), where B is the magnetic field, μ_0 is the permeability of free space (4π x 10^-7 T·m/A), n is the number of turns per unit length, and I is the current through the solenoid.

The magnetic flux Φ through the solenoid can be calculated using the formula Φ = B * A, where A is the cross-sectional area of the solenoid.

In your case, to compute the magnetic field, you would first calculate the number of turns per unit length by dividing the total number of turns by the length of the solenoid.

Then multiply this by the current (assuming you have that value) and the permeability of free space. For the magnetic flux, calculate the area using the diameter of the solenoid and then use the value of B to find Φ.

User Shishir
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